Filtration Experiment

Aim: Separate a mixture we have made using filtration.

Hypothesis: By filtrating, the mixture, which they are both liquids( Copper Sulfate & Sodium carbonate), the liquid will turn pale blue, it will not separate because they got the same size particles.

METHOD:

1. Pour approximately 50mL of Copper Sulfate solution into a beaker.

2. Add the same volume of sodium carbonate solution. A reaction will happen, you should see a cloudy blue precipitate form called copper carbonate.

 

3.fold filter paper to fit inside the funnel

4. Place the funnel with the filter paper inside of it, into the mouth of a conical flask.

 

5. we Stirred the mixture in the beaker, then carefully pour it into the funnel. 

6. Observe what happened.

(Hypothesis is wrong)

Results: We started with clear and light blue chemicals that were both see-through, then we mixed them and they went to a non-see-through solid in the water. Then we filtered them and we waited for the filtration to happen and finally, we saw that it made a clear liquid the non-see-through part was a solid, filtering it removed the solid which is the copper carbonate. Why did this happen? This happened because the copper carbonate was mixed into the Sodium Carbonate, which then has made the blue solid precipitate. After Filtrating the combined mixture the Sodium Carbonate has been separated from the Copper Sulfate because the Copper Sulfate has been turned into a solid. making the Copper Sulfate go down the funnel.

Copper Sulfate + Sodium Carbonate ----> Copper Carbonate + Sodium Sulfate + Sodium Sulfate.

                                                                   Insoluble